[[pole10]]
 
#include <iostream>
 
using namespace std;
const int N= 10;
int a[N];
void tisk (int p[N])
{
    for (int j=0; j<N; j++)
    {
        cout << "p[" << j << "]=" << p[j] << endl;
    }
}
int main()
{
    a[0]=1;
    for (int i=1; i<N; i++)
    {
        // a[i]= 2 * a[i-1]; // mocniny 2
        a[i]= i * a[i-1]; // faktorialy
    }
    tisk (a);
    cout << "KONEC" << endl;
    return 0;
}
#include <iostream>
 
using namespace std;
const int N= 10;
int a[N];
void tisk (int p[N], int k)
{
    for (int j=0; j<k; j++)
    {
        cout << p[j] << " ";
    }
    cout<< endl;
}
int main()
{
    a[0]=1;
    tisk (a, 1);
    for (int k=1; k<=N-1; k++)
    {
       int b [N];
       b[0]=1;
       for (int i=1; i<= k-1; i++)
       {
           b[i]=a[i]+a[i-1];
       }
       b[k]= 1;
       tisk (b, k+1);
       for (int i=0; i<=k; i++)
       {
           a[i]=b[i];
       }
    }
 
    cout << "KONEC" << endl;
    return 0;
}
#include <iostream>
 
using namespace std;
const int N= 10;
int a[N][N];
void tisk (int p[N], int k)
{
    for (int j=0; j<k; j++)
    {
        cout << p[j] << " ";
    }
    cout<< endl;
}
 
int komb (int n, int k)
{
    if (k == 0 || k == n || n == 0)
       return 1;
    else
       return komb (n-1, k-1) + komb (n-1, k);
}
int main()
{
 
    for (int i = 0; i < N; i++)
    {
        for (int k = 0; k <= i; k++)
        {
            cout << komb (i, k) << " ";
        }
        cout << endl;
    }
 
    for (int i = 0; i < N; i++)
        for (int j = 0; j < N; j++)
            a[i][j] = 0;
 
    a[0][0]= 1;
    tisk (a[0], 1);
 
    for (int k=1; k<=N-1; k++)
    {
       a[k][0]= 1;
       for (int i=1; i<= k-1; i++)
       {
           a[k][i]=a[k-1][i]+a[k-1][i-1];
       }
       a[k][k]= 1;
       tisk (a[k], k+1);
    }
 
    cout << "KONEC" << endl;
    return 0;
}
#include <iostream>
 
using namespace std;
const int N = 10;
int a[N];
void tisk (int p[N], int k)
{
    for (int j=0; j<k; j++)
    {
        cout << p[j] << " ";
    }
    cout<< endl;
}
 
int main()
{
    for (int i = 0; i < N; i++)
        a[i] = 0;
 
    int v = 30; // cislo, ktere budeme prevadet
 
    int k = 0; // index, 2 ^ k
    while ( v>0 && k< N)
    {
        a[k] = v % 10;
        v /= 10;
        k++;
    }
    for (int i=N-1; i>=0; i--)
        cout << a[i] << " ";
    cout << "Konec" << endl;
    return 0;
}
 
pole10.txt · Last modified: 2018/10/18 17:05 by 147.32.8.115
 
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